The correct option for the value of vapour pressure of a solution at $45 º C$ with benzene to octane in molar ratio $3: 2$ is:
[At $45 ° C$ vapour pressure of benzene is $280mmHg$ and that of octane is $420mmHg .$ Assume Ideal gas]

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The correct option for the value of vapour pressure of a solution at $45 º C$ with benzene to octane in molar ratio $3: 2$ is:

[At $45 ° C$ vapour pressure of benzene is $280mmHg$ and that of octane is $420mmHg .$ Assume Ideal gas]

Quantrex Academy · Accepted Answer

Correct answer: C. 336mm of Hg

Given: P _ B ° = 280mm of Hg, P _ o ° = 420mm of Hg X _ B = (3)/(5) and X _ o = (2)/(5) We know that according to Raoult's Law P _ T = X _ B P _ B ^ ° + X _ o P _ o ^ ° = (3)/(5) × 280 + (2)/(5) × 420 = 336mm of Hg

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