NEET2013ChemistrySolutionsActual
6.02 10²⁰ molecules of urea are present in 100 ~mL of its solution. The concentration of solution is
Options
- A0.02 M
- B0.01 M
- C0.001 M
- D0.1 M
Correct answer
B. 0.01 M
Step-by-step solution
Given, number of molecules of urea =6.02 10²⁰ aligned & Number of moles = 6.02 10²⁰ N_A & = 6.02 10²⁰ 6.02 10²³ =1 10⁻³ ~mol aligned Volume of the solution =100 ~mL = 100 1000 ~L =0.1 ~L Concentration of urea solution aligned ( in mol L ⁻¹ ) & = 1 10⁻³ 0.1 mol L ⁻¹ & =1 10⁻² ~mol ~L ⁻¹=0.01 ~mol ~L ⁻¹ aligned