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NEET 2002
Exam
NEET
Year
2002
Subject
Chemistry
Chapter
Solutions

NEET 2002 · Chemistry · Solutions

A solution contains non-volatile solute of molecular mass M_2 ....

A solution contains non-volatile solute of molecular mass M2M_2. Which of the following can be used to calculate the molecular mass of the solute in terms of the osmotic pressure? Note: m2m_2 is the mass of the solute, V\mathrm{V} is the volume of the solution and π\pi is the osmotic pressure.

Options

  1. AM2=(m2π)VRT\mathrm{M}_2=\left(\frac{m_2}{\pi}\right) \mathrm{VRT}
  2. BM2=(m2 V)RTπ\mathrm{M}_2=\left(\frac{m_2}{\mathrm{~V}}\right) \frac{\mathrm{RT}}{\pi}
  3. CM2=(m2 V)πRT\mathrm{M}_2=\left(\frac{m_2}{\mathrm{~V}}\right) \pi \mathrm{RT}
  4. DM2=(m2 V)πRT\mathrm{M}_2=\left(\frac{m_2}{\mathrm{~V}}\right) \frac{\pi}{\mathrm{RT}}

Correct answer

B. M2=(m2 V)RTπ\mathrm{M}_2=\left(\frac{m_2}{\mathrm{~V}}\right) \frac{\mathrm{RT}}{\pi}

Step-by-step solution

For dilute solution, the van't Hoff equation is: π=n VRTπV=m2MRT⇒M=m2RTπV\begin{aligned} \pi & =\frac{n}{\mathrm{~V}} \mathrm{RT} \\ \pi \mathrm{V} & =\frac{m_2}{\mathrm{M}} \mathrm{RT} \\ \Rightarrow \quad \mathrm{M} & =\frac{m_2 \mathrm{RT}}{\pi \mathrm{V}} \end{aligned} Van't Hoff explained that when solutes are dissolved in a solvent they dissociate into ions. Since colligative properties depend only on the number of solute particles, the dissociation of solute molecules into ions results in an increase in the number of particles and hence affects the colligative properties.
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