NEET2019ChemistryThermodynamics (C)Actual
An ideal gas expands isothermally from 10⁻³ ~m ^3 to 10⁻² ~m ^3 at 300 ~K against a constant pressure of 10^5 Nm ⁻² . The work done on the gas is
Options
- A+270 ~kJ
- B-900 ~J
- C+900 k J
- D-900 k J
Correct answer
B. -900 ~J
Step-by-step solution
For an isothermal irreversible expansion, Work done ( W )=- p _ ext ( V ₂- V ₁ ) where, V ₁= initial volume V ₂= final volume Given, p _ ext =10^5 Nm ⁻², ~V ₁=10⁻³ ~m ^3, ~V ₂=10⁻² ~m ^3 On substituting the given values in Eq, (i), We get, aligned W & =-10^5 Nm ⁻² (10⁻² ~m ^3-10⁻³ ~m ^3 ) & =-10^5 Nm ⁻² 10⁻³(10-1) m ^3 & =-900 Nm =-900 ~J aligned