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NEET 2019
Exam
NEET
Year
2019
Subject
Chemistry
Chapter
Thermodynamics (C)

NEET 2019 · Chemistry · Thermodynamics (C)

Reversible expansion of an ideal gas under isothermal and adiabatic...

Reversible expansion of an ideal gas under isothermal and adiabatic conditions are as shown in the figure. Reversible expansion of an ideal gas under isothermal and adiabatic conditions are as shown in the figure. A B arrow
AB→A B \rightarrow Isothermal expansion AC→A C \rightarrow Adiabatic expansion Which of the following option is not correct?

Options

  1. AΔSisothermal >ΔSadiabatic \Delta S_{\text{isothermal }}>\Delta S_{\text{adiabatic }}
  2. BTA=TBT_A=T_B
  3. CWisothermal >Wadiabatic W_{\text{isothermal }}>W_{\text{adiabatic }}
  4. DTc>TAT_c>T_A

Correct answer

D. Tc>TAT_c>T_A

Step-by-step solution

From first law of thermodynamics, Δ\Delta\mathrm{U}=\mathrm{q}+W+\mathrm{W}In adiabatic expansion, q=0q=0 \therefore \quad ΔU=W\Delta \mathrm{U}=\mathrm{W}During expansion of a gas ww is negative i.e w<0w \lt 0 or ΔU<0\Delta \mathrm{U} \lt 0. We know that, Δ\Delta\mathrm{U}=\mathrm{nC}VΔT_{\mathrm{V}} \Delta \mathrm{T} ∴nCVΔT<0 or ΔT<0∴TC−TA<0 or TC<TA\begin{array}{lclc} \therefore& \mathrm{nC}_{\mathrm{V}} \Delta \mathrm{T}< 0 & \text{ or }& \Delta \mathrm{T}< 0 \\ \therefore & \mathrm{T}_{\mathrm{C}}-\mathrm{T}_{\mathrm{A}}< 0 & \text{ or }& \mathrm{T}_{\mathrm{C}}< \mathrm{T}_{\mathrm{A}} \end{array}Thus, option (4) is incorrect while the remaining options are correct.
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