Under the isothermal condition, a gas at 300   K expands from 0.1   L to 0.25   L against a constant external pressure of 2 bar. The work done by the gas is (Given that 1   L bar = 100   J )

Step-by-step solution

The work done by a gas, W = P external × ΔV = - 2 × v 2 - v 1 = - 2 × 0.25 - 0.10 = - 0.30   L bar Given, 1   L bar = 100   J . So, W = - 0 .3 × 100 = - 30   J .