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NEET 2019
Exam
NEET
Year
2019
Subject
Chemistry
Chapter
Thermodynamics (C)

NEET 2019 · Chemistry · Thermodynamics (C)

Under the isothermal condition, a gas at 300K expands from 0.1L to...

Under the isothermal condition, a gas at 300K300K expands from 0.1L0.1L to 0.25L0.25L against a constant external pressure of 22 bar. The work done by the gas is

(Given that 1L1L bar=100J= 100J)

Options

  1. A−30J- 30J
  2. B5kJ5kJ
  3. C25J25J
  4. D30J30J

Correct answer

A. −30J- 30J

Step-by-step solution

The work done by a gas,

W=Pexternal×ΔVW = {P}_{external} \times \Delta V

=−2×(v2−v1)= - 2 \times \left({v}_{2} - {v}_{1}\right)

=−2×(0.25−0.10)= - 2 \times \left(0.25 - 0.10\right)

=−0.30L= - 0.30L bar

Given, 1L1L bar =100J= 100J.

So, W=−0.3×100=−30JW = - 0 .3 \times 100 = - 30J.
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