NEET2012ChemistryThermodynamics (C)Actual
The enthalpy of fusion of water is 1.435 kcal / mol . The molar entropy change for the melting of ice at 0^ C is
Options
- A10.52 cal /( mol K )
- B21.04 cal /( mol K )
- C5.260 cal /( mol K )
- D0.526 cal /( mol K )
Correct answer
C. 5.260 cal /( mol K )
Step-by-step solution
Molar entropy change for the melting of ice, aligned S_ melt & = H_ fusion T & = 1.435 kcal / mol (0+273) K & =5.26 10⁻³ kcal / mol K & =5.26 cal / mol K aligned