For the reaction C_3 H_8(g)+5 O_2(g) arrow 3 CO_2(~g)+4 H_2 O(l) at constant temperature, Δ H-Δ E is:

Correct answer: B. -3 RT aligned C_3 H_ 8(g) +50_ 2(g) & arrow 3 CO_ 2(~g) +4 H_2 O_ (i) Δ n & =3-6=-3 Δ H & =Δ E+P Δ V aligned or Δ H-Δ E=P Δ V Δ H-Δ E=Δ nRT=-3 RT

NEET 2003

Exam: NEET
Year: 2003
Subject: Chemistry
Chapter: Thermodynamics (C)

NEET 2003 · Chemistry · Thermodynamics (C)

For the reaction C_3 H_8(g)+5 O_2(g) arrow 3 CO_2(~g)+4 H_2 O(l) at...

For the reaction

\mathrm{C}_3 \mathrm{H}_8(g)+5 \mathrm{O}_2(g) \rightarrow 3 \mathrm{CO}_2(\mathrm{~g})+4 \mathrm{H}_2 \mathrm{O}(l)

at constant temperature,

\Delta \mathrm{H}-\Delta \mathrm{E}

is:

Options

A+RT
B-3 RT
C+3 RT
D-RT

Correct answer

B. -3 RT

Step-by-step solution

\begin{aligned} \mathrm{C}_3 \mathrm{H}_{8(g)}+50_{2(g)} & \rightarrow 3 \mathrm{CO}_{2(\mathrm{~g})}+4 \mathrm{H}_2 \mathrm{O}_{(i)} \\ \Delta n & =3-6=-3 \\ \Delta \mathrm{H} & =\Delta \mathrm{E}+\mathrm{P} \Delta \mathrm{V} \end{aligned}

\Delta \mathrm{H}-\Delta

\mathrm{E}=\mathrm{P}

\Delta \mathrm{V} \Delta \mathrm{H}-\Delta \mathrm{E}=\Delta \mathrm{nRT}=-3 \mathrm{RT}

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