NEET2003ChemistryThermodynamics (C)Actual
The densities of graphite and diamond at 298 ~K are 2.25 and 3.31 gcm ⁻³ , respectively. If the standard free energy difference ( G ^ ) is equal to 1895 ~J ~mol ⁻¹ , the pressure at which graphite will be transformed into diamond at 298 ~K is:
Options
- A9.92 10^8 ~Pa
- B9.92 10^7 ~Pa
- C9.92 10^6 ~Pa
- Dnone
Correct answer
D. none
Step-by-step solution
G =- P V aligned & 1895=P [ ( 12 2.25 - 12 3.31 ) 10⁻⁶ ~m ^3 ] & P= 1895 10^6 1.71 =1108.187 10^6 Bar & =1108.1871 10¹¹ ~Pa aligned