To an ac power supply of 220 V at 50 Hz , a resistor of 20 , a capacitor of reactance 25 and an inductor of reactance 45 are connected is series. The corresponding current in the circuit and the phase angle between the

Correct answer: B. 7. 8 A and 45^ aligned & X_ C =25 & X_ L =45 & Z= R^2+(X_ L -X_ C )^2 & Z= 20^2+(45-25)^2 & Z=20 2 aligned aligned & I_ r m s = V_ r m s Z = 220 20 2 = 11 2 =7.8 ~A & φ=(X_L-X_C)/(R)=(45-25)/(20)=(20)/(20)=1 & φ=45^ aligned

NEET 2025

Exam: NEET
Year: 2025
Subject: Physics
Chapter: Alternating Current

NEET 2025 · Physics · Alternating Current

To an ac power supply of 220 V at 50 Hz , a resistor of 20 , a...

To an ac power supply of 220 V at 50 Hz , a resistor of

20 \Omega

, a capacitor of reactance

25 \Omega

and an inductor of reactance

45 \Omega

are connected is series. The corresponding current in the circuit and the phase angle between the current and the voltage is, respectively-

Options

A7.8 A and $30^{\circ}$
B7. 8 A and $45^{\circ}$
C15.6 and $30^{\circ}$
D15.6 and $45^{\circ}$

Correct answer

B. 7. 8 A and $45^{\circ}$

Step-by-step solution

\begin{aligned} & \mathrm{X}_{\mathrm{C}}=25 \Omega \\ & \mathrm{X}_{\mathrm{L}}=45 \Omega \\ & \mathrm{Z}=\sqrt{\mathrm{R}^2+\left(\mathrm{X}_{\mathrm{L}}-\mathrm{X}_{\mathrm{C}}\right)^2} \\ & \mathrm{Z}=\sqrt{20^2+(45-25)^2} \\ & \mathrm{Z}=20 \sqrt{2}\end{aligned}

\begin{aligned} & I_{r m s}=\frac{V_{r m s}}{Z}=\frac{220}{20 \sqrt{2}}=\frac{11}{\sqrt{2}}=7.8 \mathrm{~A} \\ & \tan \phi=\frac{X_L-X_C}{R}=\frac{45-25}{20}=\frac{20}{20}=1 \\ & \phi=45^{\circ}\end{aligned}

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