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NEET2026PhysicsAlternating CurrentActual

An ac voltage V=220 (2 10^3 t) Volt is applied to a series LCR circuit. Then the current amplitude in this circuit is : (Given : L=10 mH, C=25 , F, R=100 , )

Options

  1. A22.0 A
  2. B2.2 A
  3. C5.5 A
  4. D11.0 A

Correct answer

B. 2.2 A

Step-by-step solution

Given V = 220 (2 10^3 t) V, the peak voltage is V_m = 220 V and the angular frequency is = 2 10^3 rad/s. The inductive reactance is X_L = L = (2 10^3) (10 10⁻³) = 20 , . The capacitive reactance is X_C = 1 C = 1 (2 10^3) (25 10⁻⁶) = 1 50 10⁻³ = 20 , . Since X_L = X_C , the circuit is in resonance. The impedance of the circuit is Z = R^2 + (X_L - X_C)^2 = R = 100 , . The current amplitude is I_m = V_m Z = 220 100 = 2.2 A. Answer: 2.2 A

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