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NEET 2024
Exam
NEET
Year
2024
Subject
Physics
Chapter
Alternating Current

NEET 2024 · Physics · Alternating Current

In the circuit shown below, the inductance L is connected to an ac...

In the circuit shown below, the inductance LL is connected to an ac source. The current flowing in the circuit is I=I0sin⁡ωtI=I_0 \sin \omega t. The voltage drop (VL)\left(V_L\right) across LL is In the circuit shown below, the inductance L is connected to an ac source. The current flowing in the circuit is I=I_0

Options

  1. AωLl0sin⁡ωt\omega L l_0 \sin \omega t
  2. BI0ωLsin⁡ωt\frac{I_0}{\omega L} \sin \omega t
  3. CI0ωLcos⁡ωt\frac{I_0}{\omega L} \cos \omega t
  4. DωLI0cos⁡ωt\omega L I_0 \cos \omega t

Correct answer

D. ωLI0cos⁡ωt\omega L I_0 \cos \omega t

Step-by-step solution

VLV_L leads current // by π2\frac{\pi}{2} VL=V0sin⁡V_L=V_0 \sin\left(\omega t+\frac{\pi}{2}\right) \quad\left(\because I=I_0 \sin \omega t\right)V0=I0XLV_0=I_0 X_L ⇒VL=10XLcos⁡(ωt)=10ωLcos⁡(ωt)\Rightarrow V_L=10 X_L \cos (\omega t)=10 \omega L \cos (\omega t)
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