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NEET2024PhysicsAlternating CurrentActual

A 10 F capacitor is connected to a 210 ~V , 50 ~Hz source as shown in figure. The peak current in the circuit is nearly ( =3.14) :

Options

  1. A0.93 A
  2. B1.20 A
  3. C0.35 ~A
  4. D0.58 A

Correct answer

A. 0.93 A

Step-by-step solution

Capacitive Reactance aligned X_C & = 1 C = 1 2 f C = 1 2 3.14 50 10 10⁻⁶ & = 1000 3.14 aligned aligned & V_ rms =210 ~V & i_ rms = V_ rms X_C = 210 X_C aligned aligned Peak current & = 2 i_ ms = 2 210 1000 3.14=0.932 & 0.93 ~A aligned

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