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NEET 2011
Exam
NEET
Year
2011
Subject
Physics
Chapter
Alternating Current

NEET 2011 · Physics · Alternating Current

In an AC circuit an alternating voltage e=200 2 100 t volt is...

In an AC\mathrm{AC} circuit an alternating voltage e=2002sin⁡100te=200 \sqrt{2} \sin 100 t volt is connected to a capacitor of capacity 1μF1 \mu \mathrm{F}. The rms value of the current in the circuit is

Options

  1. A100 mA100 \mathrm{~mA}
  2. B200 mA200 \mathrm{~mA}
  3. C20 mA20 \mathrm{~mA}
  4. D10 mA10 \mathrm{~mA}

Correct answer

C. 20 mA20 \mathrm{~mA}

Step-by-step solution

Given, e=2002sin⁡100te=200 \sqrt{2} \sin 100 t and C=1μFErms=200 VXC=1ωC=11×10−6×100=104Ωirms=ErmsXCirms=200104=2×10−2 A=20 mA\begin{aligned}C & =1 \mu \mathrm{F}\\ E_{\mathrm{rms}} & =200 \mathrm{~V}\\ X_C & =\frac{1}{\omega C}=\frac{1}{1 \times 10^{-6} \times 100}=10^4 \Omega \\ i_{\mathrm{rms}} & =\frac{E_{\mathrm{rms}}}{X_C}\\ i_{\mathrm{rms}} & =\frac{200}{10^4}=2 \times10^{-2} \mathrm{~A}=20 \mathrm{~mA} \end{aligned}
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