An AC voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are both equal to 3 , the phase difference between the applied voltage and the current in the circuit is

Correct answer: A. π / 4 aligned φ=(X_L)/(R)& =(L ω)/(R) φ & =(3 )/(3 ) φ & =1 φ & = ^ -1 (1) φ & =45^ ^ φ & =(π)/(4) rad aligned

NEET 2011

NEET 2011 · Physics · Alternating Current

An AC voltage is applied to a resistance R and an inductor L in...

An AC voltage is applied to a resistance

R

and an inductor

L

in series. If

R

and the inductive reactance are both equal to

3 \Omega

, the phase difference between the applied voltage and the current in the circuit is

A. $\pi / 4$

\begin{aligned} \tan \phi=\frac{X_L}{R}& =\frac{L \omega}{R}\\ \tan \phi & =\frac{3 \Omega}{3 \Omega}\\ \tan \phi & =1 \\ \phi & =\tan ^{-1}(1) \\ \phi & =45^{{}^{\circ}} \\ \phi & =\frac{\pi}{4} \mathrm{rad} \end{aligned}