Match List I with List II. |c| List I (Spectral Lines of Hydrogen for transitions from) |c| List II (Wavelengths (nm)) A. n_2=3 to m_1=2 I. 410.2 B. n_2=4 to m_1=2 II. 434.1 C. n_2=5 to n_1=2 III. 656.3 D. n_2=6 to

Correct answer: A. A-III, B-IV, C-III, D-I Energy difference Δ E=(h c)/(λ) aligned & λ (1)/(Δ E) & (Δ E)_ 6-2 (Δ E)_ 5-2 (Δ E)_ 4-2 (Δ E)_ 3-2 & λ_ 6-2 λ_ 5-2 λ_ 4-2 λ_ 3-2 aligned A-III, B-IV, C-II, D-I

NEET 2024

Exam: NEET
Year: 2024
Subject: Physics
Chapter: Atomic Physics

NEET 2024 · Physics · Atomic Physics

Match List I with List II. |c| List I (Spectral Lines of Hydrogen...

Match List I with List II.

	{\|c\|}{ $<table class="qx-match-list qx-match-table" border="1" cellpadding="6" cellspacing="0"><tr><td>List I</td></tr><tr><td>(Spectral Lines of</td></tr><tr><td>Hydrogen for</td></tr><tr><td>transitions from)</td></tr></table>}</td><td>$	{\|c\|}{ $<table class="qx-match-list qx-match-table" border="1" cellpadding="6" cellspacing="0"><tr><td>List II</td></tr><tr><td>(Wavelengths (nm))</td></tr></table>}</td></tr><tr><td>A.$	n_2=3 to m_1=2	I.	410.2
B.	n_2=4 to m_1=2	II.	434.1
C.	n_2=5 to n_1=2	III.	656.3
D.	n_2=6 to n_1=2	IV.	486.1

Choose the correct answer from the options given below:

Options

AA-III, B-IV, C-III, D-I
BA-IV, B-III, C-I, D-II
CA-I, B-II, C-III, D-IV
DA-II, B-I, C-IV, D-III

Correct answer

A. A-III, B-IV, C-III, D-I

Step-by-step solution

Energy difference

\Delta E=\frac{h c}{\lambda}

\begin{aligned} & \therefore \lambda \propto \frac{1}{\Delta E} \\ & (\Delta E)_{6-2}\gt(\Delta E)_{5-2}\gt(\Delta E)_{4-2}\gt(\Delta E)_{3-2} \\ & \lambda_{6-2} \lt \lambda_{5-2} \lt \lambda_{4-2} \lt \lambda_{3-2} \end{aligned}

$$ A-III, B-IV, C-II, D-I

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