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NEET 2012
Exam
NEET
Year
2012
Subject
Physics
Chapter
Atomic Physics

NEET 2012 · Physics · Atomic Physics

An electron of a stationary hydrogen atom passes from the fifth...

An electron of a stationary hydrogen atom passes from the fifth energy level to the ground level. The velocity that the atom acquired as a result of photon emission will be ( mm is the mass of the electron, RR Rydberg constant and hh Planck's constant)

Options

  1. A24hR25m\frac{24 h R}{25 m}
  2. B25hR24m\frac{25 h R}{24 m}
  3. C25m24hR\frac{25 m}{24 h R}
  4. D24m25hR\frac{24 m}{25 h R}

Correct answer

A. 24hR25m\frac{24 h R}{25 m}

Step-by-step solution

Here, E5−E1=hcλRhc25−Rhc=hcλ2425R=1λE_5-E_1=\frac{h c}{\lambda} \begin{gathered} \frac{R h c}{25}-R h c=\frac{h c}{\lambda} \\ \frac{24}{25} R=\frac{1}{\lambda} \end{gathered} But P=hλv=hmλ=2425Rhm\begin{aligned} P & =\frac{h}{\lambda} \\ v & =\frac{h}{m \lambda} \\ & =\frac{24}{25} \frac{R h}{m} \end{aligned}
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