Electron in hydrogen atom first jumps from third excited state to second excited state and then from second excited to the first excited state. The ratio of the wavelengths λ_1: λ_2 emitted in the two cases is

Question

Quantrex Academy · Accepted Answer

Correct answer: D. 20 / 7

Here, for wavelength λ_1 n_1=4 and n_2=3 and for λ_2, n_1=3 and n_2=2 We have (h c)/(λ)=-13.6 [(1)/(n_2^2)-(1)/(n_1^2)] So, for λ_1 aligned (h c)/(λ_1) & =-13.6[(1)/((4)^2)-(1)/((3)^2)] (h c)/(λ_1) & =13.6[(7)/(144)] aligned Similarly, for λ_2 aligned (h c)/(λ_2) & =-13.6[(1)/((3)^2)-(1)/((2)^2)] (h c)/(λ_2) & =13.6[(5)/(36)] aligned Hence, from Eqs. (i) and (ii), we get (λ_1)/(λ_2)=(20)/(7)

Electron in hydrogen atom first jumps from third excited state to...

Options

Correct answer

Step-by-step solution

More from Atomic Physics