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NEET 2013
Exam
NEET
Year
2013
Subject
Physics
Chapter
Atomic Physics

NEET 2013 · Physics · Atomic Physics

Ratio of longest wavelengths corresponding to Lyman and Balmer...

Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is

Options

  1. A527\frac{5}{27}
  2. B323\frac{3}{23}
  3. C729\frac{7}{29}
  4. D931\frac{9}{31}

Correct answer

A. 527\frac{5}{27}

Step-by-step solution

Wavelength for Lyman series \lambda_L=1R(1−14)=43R\frac{1}{R\left(1-\frac{1}{4}\right)}=\frac{4}{3 R}and wavelength for Balmer seriesλB=1R(14−19)=1R(536)=365R∴λLλB=43R×5R36=527⇒λL:λB=5:27\begin{aligned}& \lambda_B=\frac{1}{R\left(\frac{1}{4}-\frac{1}{9}\right)}=\frac{1}{R\left(\frac{5}{36}\right)}=\frac{36}{5 R}\\ & \therefore \quad \frac{\lambda_L}{\lambda_B}=\frac{4}{3 R} \times \frac{5 R}{36}=\frac{5}{27}\\ & \Rightarrow \quad \lambda_L: \lambda_B=5: 27 \\ & \end{aligned}
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