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NEET2013PhysicsAtomic PhysicsActual

Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is

Options

  1. A5 27
  2. B3 23
  3. C7 29
  4. D9 31

Correct answer

A. 5 27

Step-by-step solution

Wavelength for Lyman series _L= 1 R (1- 1 4 ) = 4 3 R and wavelength for Balmer series aligned & _B= 1 R ( 1 4 - 1 9 ) = 1 R ( 5 36 ) = 36 5 R & _L _B = 4 3 R 5 R 36 = 5 27 & _L: _B=5: 27 & aligned

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