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NEET2009PhysicsAtomic PhysicsActual

The ionization energy of the electron in the hydrogen atom in its grounds state is 13.6 eV . The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between :

Options

  1. An=4 to n=3 states
  2. Bn=3 to n=2 states
  3. Cn=3 to n=1 states
  4. Dn=2 to n=1 states

Correct answer

A. n=4 to n=3 states

Step-by-step solution

aligned & n ( n -1) 2 =6 & n =4 aligned For maximum wavelength energy difference between states should be minimum because = hc E So, transition state in n =4 to n =3

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