The ionization energy of the electron in the hydrogen atom in its grounds state is 13.6 eV . The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation

NEET 2009

Exam: NEET
Year: 2009
Subject: Physics
Chapter: Atomic Physics

NEET 2009 · Physics · Atomic Physics

The ionization energy of the electron in the hydrogen atom in its...

The ionization energy of the electron in the hydrogen atom in its grounds state is

13.6 \mathrm{eV}

. The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between :

Options

A $n=4$ to $n=3$ states
B $n=3$ to $n=2$ states
C $n=3$ to $n=1$ states
D $n=2$ to $n=1$ states

Correct answer

A. $n=4$ to $n=3$ states

Step-by-step solution

\begin{aligned} & \frac{\mathrm{n}(\mathrm{n}-1)}{2}=6 \\ \Rightarrow & \mathrm{n}=4\end{aligned}

For

maximum wavelength energy difference between states should be minimum because \lambda=

\frac{\mathrm{hc}}{\Delta \mathrm{E}}

So, transition state in

\mathrm{n}=4 to \mathrm{n}=3$

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