The equivalent capacitance of the system shown in the following circuit is:

Step-by-step solution

For parallel grouping(the loop part), equivalent capacitance can be written as C p = 3 + 3   μF = 6   μF . Now, this part is in series with the left capacitor. So we can write C e q = 3 × 6 3 + 6   μF = 2   μF