The effective capacitances of two capacitors are 3 F and 16 F , when they are connected in series and parallel respectively. The capacitance of two capacitors are:

Step-by-step solution

given: (C_S=3 M f ) ( aligned & C_P=16 M f & as C_S= [ (C₁ C₂ ) / (C₁+C₂ ) ]=3 & C_P=C₁+C₂=16(2) & from (1), [ (C₁ C₂ ) /(16) ]=3 & C₁ C₂=48 & from (2), C₂=16-C₁ & C₂=16- (48 / C₂ ) & C₂+ (48 / C₂ )=16 & C₂^2+48-16 C₂=0 & C₂=12 F, C₂=4 F aligned ) i.e. capacitance are (4 F ~ &~ 12 F )