NEET2010PhysicsCapacitanceActual
A series combination of n₁ capacitors, each of value C ₁ , is charged by a source of potential difference 4 ~V . When another parallel combination of n₂ capacitors, each of value C₂ , is charged by a source of potential difference V , it has the same (total) energy stored in it, as the first combination has. The value of C ₂ , in terms of C ₁ , is then
Options
- A2 C ₁ n ₁ n ₂
- B16 n ₂ n ₁ C ₁
- C2 n ₂ n ₁ C ₁
- D16 C₁ n₁ n₂
Correct answer
D. 16 C₁ n₁ n₂
Step-by-step solution
P.D. across each capacitor is (V₁= 4 ~V n ₁ ) Energy stored across the combination is ( U ₁= n ₁ 1 2 C ₁ 16 ~V ^2 n ₁^2 = 16 C ₁ ~V ^2 2 n ₁ ) ( aligned & Energy stored across parallel combination is U ₂= n ₂ 1 2 C ₂ ~V ^2 & 16 C₁ v^2 2 n₁ = n₂ C₁ v^2 2 & C₂= 16 C₁ n₁ n₂ aligned )