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An electron and an alpha particle are accelerated by the same potential difference. Let _ and _a denote the de-Broglie wavelengths of the electron and the alpha particle, respectively, then:

Options

  1. A_e _
  2. B_e=4 _
  3. C_e=
  4. D_e _a

Correct answer

A. _e _

Step-by-step solution

de-Broglie wavelength is given by = h p = h 2 m q V For same potential difference 1 m q _ _e = m_e q_e m_ q_ m_ m_e _e _

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