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The graph which shows the variation of ( 1 ^2 ) and its kinetic energy, E is (where is de Broglie wavelength of a free particle):

Correct answer

2

Step-by-step solution

de-Broglie wavelength = h P = h m v = h 2 m E where E= 1 2 m v^2 Squaring both sides, aligned & ^2= h^2 4 m^2 E & 1 ^2 = (constant) E aligned Graph passes through origin with constant slope.

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