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NEET 2023
Exam
NEET
Year
2023
Subject
Physics
Chapter
Electrostatics

NEET 2023 · Physics · Electrostatics

If a conducting sphere of radius R is charged. Then the electric...

If a conducting sphere of radius RR is charged. Then the electric field at a distance r(r>R)r(r>R) from the centre of the sphere would be, (V=(V= potential on the surface of the sphere ))

Options

  1. ARVr2\frac{R V}{r^2}
  2. BVr\frac{V}{r}
  3. CrVR2\frac{r V}{R^2}
  4. DR2Vr3\frac{R^2 V}{r^3}

Correct answer

A. RVr2\frac{R V}{r^2}

Step-by-step solution

For r>Rr>R, Electric field E=Kqr2…E=\frac{K q}{r^2} \ldots and potential at surface of sphere V=KqRV=\frac{K q}{R} ∴\therefore From equation (1) V=Er2RV=\frac{E r^2}{R} ⇒E=RVr2\Rightarrow E=\frac{R V}{r^2}
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