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NEET2023PhysicsElectrostaticsActual

If a conducting sphere of radius R is charged. Then the electric field at a distance r(r>R) from the centre of the sphere would be, (V= potential on the surface of the sphere )

Options

  1. AR V r^2
  2. BV r
  3. Cr V R^2
  4. DR^2 V r^3

Correct answer

A. R V r^2

Step-by-step solution

For r>R , Electric field E= K q r^2 and potential at surface of sphere V= K q R From equation (1) V= E r^2 R E= R V r^2

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