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NEET 2023
Exam
NEET
Year
2023
Subject
Physics
Chapter
Electrostatics

NEET 2023 · Physics · Electrostatics

An electric dipole is placed at an angle of 30 ° with an electric...

An electric dipole is placed at an angle of 30°30 ° with an electric field of intensity 2×105NC−12 \times {10}^{5}N{C}^{- 1}. It experiences a torque equal to 4Nm4Nm. Calculate the magnitude of charge on the dipole, if the dipole length is 2cm2cm.

Options

  1. A2mC2mC
  2. B8mC8mC
  3. C6mC6mC
  4. D4mC4mC

Correct answer

A. 2mC2mC

Step-by-step solution

Torque experienced by the electric dipole is given by,

∣τ→∣=∣p→×E→∣⇒4=pEsinθ⇒4=(ql)×(2×105)×sin⁡30°⇒q=4105×(2×10−2)=2×10−3C=2mC\left|\overset{\to}{τ}\right| = \left|\overset{\to}{p} \times \overset{\to}{E}\right| ⇒ 4 = pEsin\theta ⇒ 4 = \left(ql\right) \times \left(2 \times {10}^{5}\right) \times \sin 30 ° ⇒ q = \dfrac{4}{{10}^{5} \times \left(2 \times {10}^{- 2}\right)} = 2 \times {10}^{- 3}C = 2mC

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