A short electric dipole has a dipole moment of $16 \times {10}^{– 9}Cm$ . The electric potential due to the dipole at a point at a distance of $0.6m$ from the centre of the dipole, situated on a line making an angle of $60 °$ with the dipole axis is:
$\left(\dfrac{1}{4\pi{ε}_{0}} = 9 \times {10}^{9}N{m}^{2}{C}^{- 2}\right)$

Question

A short electric dipole has a dipole moment of

16 \times {10}^{– 9}Cm

. The electric potential due to the dipole at a point at a distance of

0.6m

from the centre of the dipole, situated on a line making an angle of

60 °

with the dipole axis is:

\left(\dfrac{1}{4\pi{ε}_{0}} = 9 \times {10}^{9}N{m}^{2}{C}^{- 2}\right)

Quantrex Academy · Accepted Answer

Correct answer: A. 200V

We know that, Electric dipole potential, V = 1 4π ε _ ∘ pcos(θ) r ^ 2 , for large distance of r . V = kPcosθ r ^ 2 = 9 × 10 ^ 9 × 16 × 10 ^ - 9 ( 0 .6 ) ^ 2 × (1)/(2) V = 200V

A short electric dipole has a dipole moment of 16 × 10 ^ – 9 Cm ....

Options

Correct answer

Step-by-step solution

More from Electrostatics