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NEET 2008
Exam
NEET
Year
2008
Subject
Physics
Chapter
Electrostatics

NEET 2008 · Physics · Electrostatics

A thin conducting ring of radius R is given a charge +Q . The...

A thin conducting ring of radius RR is given a charge +Q+Q. The electric field at the centre OO of the ring due to the charge on the part AKBA K B of the ring is EE. The electric field at the centre due to the charge on the part ACDBA C D B of the ring is A thin conducting ring of radius R is given a charge +Q . The electric field at the centre O of the ring due to the

Options

  1. A3E3 \mathrm{E} along KO\mathrm{KO}
  2. BE along OKO K
  3. CEE along KOK O
  4. D3E3 E along OKO K

Correct answer

B. E along OKO K

Step-by-step solution

Key Idea: It is given that the ring is conducting. As the ring is conducting, so electric field at its centre is zero, ie, \overrightarrow{\mathbf{E}_{\text{total }}=0\begin{aligned} \overrightarrow{\mathbf{E}_{A K B}+\overrightarrow{\mathbf{E}_{A C D B} & =0 \\ \overrightarrow{\mathbf{E}_{A C D B} & =-\overrightarrow{\mathbf{E}_{A K B} \\ \overrightarrow{\mathbf{E}_{A C D B} & =-\overrightarrow{\mathbf{E}} \text{ (along } K O \text{ ) } \end{aligned}$Therefore,theelectricfieldatthecentreduetothechargeonthepartACDBTherefore, the electric field at the centre due to the charge on the part A C D B of the ring is EE along OKO K. lternative : The fields at OO due to A C and B Dcanceleachother.Thefieldduetocancel each other. The field due toC Disactinginthedirectionis acting in the directionO Kandequalinmagnitudetoand equal in magnitude toE$ due to A K B.
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