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NEET2008PhysicsElectrostaticsActual

A thin conducting ring of radius R is given a charge + Q . The electric field at the centre O of the ring due to the charge on the part AKB of the ring is E . The electric field at the centre due to the charge on the part ACDB of the ring is

Options

  1. A3 E along OK
  2. B3 E along KO
  3. CE along OK
  4. DE along KO

Correct answer

C. E along OK

Step-by-step solution

aligned E ₀ & =0 E _ A K B + E _ A C D B & =0 E _ A C D B & = ^ (-) E _ A K B & =-E( along K O) & =E( along O K) aligned

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