NEET2008PhysicsElectrostaticsActual
A thin conducting ring of radius R is given a charge + Q . The electric field at the centre O of the ring due to the charge on the part AKB of the ring is E . The electric field at the centre due to the charge on the part ACDB of the ring is
Options
- A3 E along OK
- B3 E along KO
- CE along OK
- DE along KO
Correct answer
C. E along OK
Step-by-step solution
aligned E ₀ & =0 E _ A K B + E _ A C D B & =0 E _ A C D B & = ^ (-) E _ A K B & =-E( along K O) & =E( along O K) aligned