A thin conducting ring of radius R is given a charge +Q . The electric field at the centre O of the ring due to the charge on the part AKB of the ring is E . The electric field at the centre due to the charge on the

Correct answer: C. E along OK aligned E _0 & =0 E _ A K B + E _ A C D B & =0 E _ A C D B & = ^ (-) E _ A K B & =-E( along ) K O) & =E( along O K) aligned

NEET 2008

Exam: NEET
Year: 2008
Subject: Physics
Chapter: Electrostatics

NEET 2008 · Physics · Electrostatics

A thin conducting ring of radius R is given a charge +Q . The...

A thin conducting ring of radius

\mathrm{R}

is given a charge

+\mathrm{Q}

. The electric field at the centre

\mathrm{O}

of the ring due to the charge on the part

\mathrm{AKB}

of the ring is

\mathrm{E}

. The electric field at the centre due to the charge on the part

\mathrm{ACDB}

of the ring is A thin conducting ring of radius R is given a charge +Q . The electric field at the centre O of the ring due to the

Options

A3 E along $\mathrm{OK}$
B3 E along $\mathrm{KO}$
CE along $\mathrm{OK}$
DE along KO

Correct answer

C. E along $\mathrm{OK}$

Step-by-step solution

\begin{aligned} \vec{E}_0 & =0 \\ \Rightarrow \quad \vec{E}_{A K B}+\vec{E}_{A C D B} & =0 \\ \vec{E}_{A C D B} & ={ }^{(-)} \vec{E}_{A K B} \\ & =-E(\text{ along }) K O) \\ & =E(\text{ along } O K) \end{aligned}

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