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NEET 2012
Exam
NEET
Year
2012
Subject
Physics
Chapter
Gravitation

NEET 2012 · Physics · Gravitation

A spherical planet has a mass M_p and diameter D_p . A particle of...

A spherical planet has a mass MpM_p and diameter DpD_p. A particle of mass mm falling freely near the surface of this planet will experience an acceleration due to gravity, equal to

Options

  1. A4GMp/Dp24 G M_p / D_p^2
  2. BGMpm/Dp2G M_p m / D_p^2
  3. CGMpm/Dp2G M_p m / D_p^2
  4. D4GMpm/Dp24 G M_p m / D_p^2

Correct answer

A. 4GMp/Dp24 G M_p / D_p^2

Step-by-step solution

Force, F=GMemR2F=\frac{G M_e m}{R^2} Here, F=GMPm(DP/2)2F=\frac{G M_P m}{\left(D_P / 2\right)^2}F=4GMPmDP2F=ma\begin{aligned} & F=\frac{4 G M_P m}{D_P^2} \\ & F=m a \end{aligned}$AccelerationduetogravityAcceleration due to gravitya=\frac{F}{m}=\frac{4 G M_P}{D_P^2}$
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