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NEET2012PhysicsGravitationActual

A geostationary satellite is orbiting the earth at a height of 5 R above that surface of the earth, R being the radius of the earth. The time period of another satellite in hours at a height of 2 R from the surface of the earth is

Options

  1. A5
  2. B10
  3. C6 2
  4. D6 / 2

Correct answer

C. 6 2

Step-by-step solution

From Keplar third's law T^2 r^3 Hence, T₁^2 r₁^3 So, aligned & T₂^2 r₂^3 & T₂^2 T₁^2 = r₂^3 r₁^3 &= (3 R)^3 (6 R)^3 aligned aligned & or T₂^2 T₁^2 = 1 8 & T₂^2= 1 8 T₁^2 & T₂= 24 2 2 =6 2 ~h aligned

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