A student measures the distance traversed in free fall of a body,...

\begin{aligned} & h=\frac{1}{2} g t^2 \\ & \text{ or } \quad g=\frac{\mathrm{h}}{\mathrm{t}^2} \\ & \therefore \quad \log \mathrm{g}=\log \mathrm{h}-2 \log \mathrm{t} \\ & \left(\frac{\Delta g}{g} \times 100\right)_{\max }=\left(\frac{\Delta \mathrm{h}}{\mathrm{h}} \times 100\right)+2\left(\frac{\Delta \mathrm{t}}{\mathrm{t}} \times 100\right) \\ & =\mathrm{e}_1+2 \mathrm{e}_2 \\ & \end{aligned}