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NEET 2005
Exam
NEET
Year
2005
Subject
Physics
Chapter
Mathematics in Physics

NEET 2005 · Physics · Mathematics in Physics

If a vector 2 i +3 j +8 k is perpendicular to the vector 4 j -4 i...

If a vector 2i^+3j^+8k^2 \hat{i}+3 \hat{j}+8 \hat{k} is perpendicular to the vector 4j^−4i^+αk^4 \hat{j}-4 \hat{i}+\alpha \hat{k} then the value of α\alpha is:

Options

  1. A12\frac{1}{2}
  2. B−12- \frac{1}{2}
  3. C1
  4. D-1

Correct answer

B. −12- \frac{1}{2}

Step-by-step solution

a⃗=2i^+3i^+8k^,b=4j^+3i^+αk^\vec{a}=2 \hat{i}+3 \hat{i}+8 \hat{k}, b=4 \hat{j}+3 \hat{i}+\alpha \hat{k}a⃗⋅b⃗=0, if a−1⋅b−1∴(2i^+3j^+8k^)⋅(−4i+4j+αk)=12⇒α=−12\begin{aligned} & \vec{a} \cdot \vec{b}=0, \text{ if } a^{-1} \cdot b^{-1} \\ & \therefore(2 \hat{i}+3 \hat{j}+8 \hat{k}) \cdot(-4 i+4 j+\alpha k)=\frac{1}{2} \\ & \Rightarrow \alpha=-\frac{1}{2} \end{aligned}$$
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