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NEET 2019
Exam
NEET
Year
2019
Subject
Physics
Chapter
Mathematics in Physics

NEET 2019 · Physics · Mathematics in Physics

In an experiment, the percentage of error occurred in the...

In an experiment, the percentage of error occurred in the measurement of physical quantities A,B,CA, B, C and DD are 1%, 2%, 3% and 4%, respectively. Then the maximum percentage of error in the measurement XX, where X=A2B12C13D3X = \dfrac{{A}^{2}B\dfrac{1}{2}}{C\dfrac{1}{3}{D}^{3}} will be

Options

  1. A(313)\left(\dfrac{3}{13}\right)%
  2. B1616%
  3. C−10- 10%
  4. D1010%

Correct answer

B. 1616%

Step-by-step solution

Given: Percentage error in AA, BB, CC and DD is 11 %, 22 %, 33 % and 44 %, respectively.

The maximum percentage error in XX is given by,

∆XX×100=2(∆AA×100)+12(∆BB×100)+13(∆CC×100)+3(∆DD×100)\dfrac{∆ X}{X} \times 100 = 2\left(\dfrac{∆ A}{A} \times 100\right) + \dfrac{1}{2}\left(\dfrac{∆ B}{B} \times 100\right) + \dfrac{1}{3}\left(\dfrac{∆ C}{C} \times 100\right) + 3\left(\dfrac{∆ D}{D} \times 100\right)

∆XX×100=2×1+12×2+13×3+3×4\dfrac{∆ X}{X} \times 100 = 2 \times 1 + \dfrac{1}{2} \times 2 + \dfrac{1}{3} \times 3 + 3 \times 4

∆XX×100=16\dfrac{∆ X}{X} \times 100 = 16%. will be the maximum percentage error in XX.

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