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NEET 2020
Exam
NEET
Year
2020
Subject
Physics
Chapter
Mechanical Properties of Solids

NEET 2020 · Physics · Mechanical Properties of Solids

A wire of length L , area of cross section A is hanging from a...

A wire of length LL, area of cross section AA is hanging from a fixed support. The length of the wire changes to L1{L}_{1} when mass MM is suspended from its free end. The expression for Young's modulus is:

Options

  1. A\dfrac{Mg\left({L}_{1} - L\right)}{AL}
  2. BMgLAL1\dfrac{MgL}{A{L}_{1}}
  3. C\dfrac{MgL}{A\left({L}_{1} - L\right)}
  4. DMgL1AL\dfrac{Mg{L}_{1}}{AL}

Correct answer

C. \dfrac{MgL}{A\left({L}_{1} - L\right)}

Step-by-step solution

We know that,

Young's modulus, Y=FLA\DeltaLY = \dfrac{FL}{A\DeltaL}

Given,

F=Weight of suspended body=MgF = \text{Weight of suspended body=}Mg and ∆L=L1−L∆ L = {L}_{1} - L.

So, we can write

Y=MgLA(L1−L)Y = \dfrac{MgL}{A\left({L}_{1} - L\right)}

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