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NEET2020PhysicsMechanical Properties of SolidsActual

A wire of length L , area of cross section A is hanging from a fixed support. The length of the wire changes to L 1 when mass M is suspended from its free end. The expression for Young's modulus is:

Options

  1. AM g L 1 − L A L
  2. BM g L A L 1
  3. CM g L A L 1 − L
  4. DM g L 1 A L

Correct answer

C. M g L A L 1 − L

Step-by-step solution

We know that, Young's modulus, Y = F L A Δ L Given, F = Weight of suspended body= M g and ∆ L = L 1 - L . So, we can write Y = M g L A L 1 - L

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