The amount of elastic potential energy per unit volume (in SI unit) of a steel wire of length 100 ~cm to stretch it by 1 ~mm is (if Young's modulus of the wire =2.0 10¹¹ ~N ~m ⁻² )

Step-by-step solution

We know that, elastic potential energy per unit volume = 1 2 Stress Strain Also, Y= Stress Strain Elastic potential energy per unit volume = 1 2 Young's modulus ( Strain )^2 aligned & = 1 2 2 10¹¹ [ 1 1000 ]^2 & = 1 2 2 10¹¹ 10⁻⁶=10^5 ( ~J / m ^3 ) aligned