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NEET 2024
Exam
NEET
Year
2024
Subject
Physics
Chapter
Motion in One Dimension

NEET 2024 · Physics · Motion in One Dimension

A particle is moving along x -axis with its position (x) varying...

A particle is moving along xx-axis with its position (x) varying with time (t)(t) as x=αt4+βt2+γt+δx=\alpha t^4+\beta t^2+\gamma t+\delta. The ratio of its initial velocity to its initial acceleration, respectively, is:

Options

  1. A2α:δ2 \alpha: \delta
  2. Bγ:2δ\gamma: 2 \delta
  3. C4α:β4 \alpha: \beta
  4. Dγ:2β\gamma: 2 \beta

Correct answer

D. γ:2β\gamma: 2 \beta

Step-by-step solution

Position of particle, x=αt4+βt2+γt+δx=\alpha t^4+\beta t^2+\gamma t+\delta Velocity v=dxdt=4αt3+2βt+γv=\frac{d x}{d t}=4 \alpha t^3+2 \beta t+\gamma Initial velocity =v(t=0)=γ=v(t=0)=\gamma Acceleration a=dvdt=12αt2+2βa=\frac{d v}{d t}=12 \alpha t^2+2 \beta Initial acceleration =a(t=0)=2β=a(t=0)=2 \beta ∴v(t=0)a(t=0)=γ2β\therefore \frac{v(t=0)}{a(t=0)}=\frac{\gamma}{2 \beta}
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