A small block slides down on a smooth inclined plane, starting from rest at time t = 0 . Let S n be the distance travelled by the block in the interval t = n - 1 to t = n . Then, the ratio s n s n + 1 is:

Step-by-step solution

As we know that the displacement covered by particle in n t h second is given by, ∵ S n t h = u + 2 n - 1 2 a but u = 0 ∴ s n = 2 n - 1 2 a       … 1 s n + 1 = 2 ( n + 1 ) - 1 2 a       … ( 2 ) Now, equation ( 1 ) divide by equation ( 2 ) s n s n + 1 = 2 n - 1 2 n + 1