NEET2014PhysicsMotion in One DimensionActual
A particle is moving such that its position coordinates x ,   y are 2   m ,   3   m at time t = 0 , 6   m ,   7   m at time t = 2   s and 13   m ,   14   m at time t = 5   s . The average velocity vector V → a v from t = 0 to t = 5   s is:
Options
- A1 5 13 i ^ + 14 j ^
- B7 3 i ^ + j ^
- C2 i ^ + j ^
- D11 5 i ^ + j ^
Correct answer
D. 11 5 i ^ + j ^
Step-by-step solution
The position vector of the particle at time t = 0 is r → i = 2 i ^ + 3 j ^ The position vector of the particle at time t = 5   s is r → f = 13 i ^ + 14 j ^ The displacement of the particle is s → = 11 i ^ + 11 j ^ The average velocity vector V → = 11 i ^ + 11 j ^ 5