NEET 2014
- Exam
- NEET
- Year
- 2014
- Subject
- Physics
- Chapter
- Motion in One Dimension
NEET 2014 · Physics · Motion in One Dimension
A particle is moving such that its position coordinates (x, y) are...
A particle is moving such that its position coordinates are \left(2m, 3m\right)t = 0, \left(6m, 7m\right) at time t = 2st = 5s. The t = 0 to t = 5s
Options
- A\dfrac{1}{5}\left(13\overset{^}{i} + 14\overset{^}{j}\right)
- B\dfrac{7}{3}\left(\overset{^}{i} + \overset{^}{j}\right)
- C2\left(\overset{^}{i} + \overset{^}{j}\right)
- D\dfrac{11}{5}\left(\overset{^}{i} + \overset{^}{j}\right)
Correct answer
D. \dfrac{11}{5}\left(\overset{^}{i} + \overset{^}{j}\right)
Step-by-step solution
The position vector of the particle at time is \overset{\to}{r}i = 2\overset{^}{i} + 3\overset{^}{j}
The position vector of the particle at time is \overset{\to}{r}f = 13\overset{^}{i} + 14\overset{^}{j}
The displacement of the particle is \overset{\to}{s} = 11\overset{^}{i} + 11\overset{^}{j}
The average velocity vector \left〈\overset{\to}{V}\right〉 = \dfrac{11\overset{^}{i} + 11\overset{^}{j}}{5}$