The displacement ' x ' (in meter) of a particle of mass ' m ' (in kg) moving in one dimension under the action of a force, is related to time ' t ' (in sec) by t= x +3 . The displacement of the particle when its velocity is zero will be:

Step-by-step solution

According to the question t= x +3 x =t-3 Squaring both sides we get x=(t-3)^2 Now velocity V= d x d t = d d t (t-3)^2=2(t-3) velocity becomes zero means aligned & 2(t-3)=0 t=3 sec . & At array l t=3 ~s x=(3-3)^2=0 m array aligned