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NEET 2011
Exam
NEET
Year
2011
Subject
Physics
Chapter
Motion in One Dimension

NEET 2011 · Physics · Motion in One Dimension

A boy standing at the top of a tower of 20 ~m height drops a stone....

A boy standing at the top of a tower of 20 m20 \mathrm{~m} height drops a stone. Assuming g=10 ms−2g=10 \mathrm{~ms}^{-2}, the velocity with which it hits the ground is

Options

  1. A20 m/s20 \mathrm{~m} / \mathrm{s}
  2. B40 m/s40 \mathrm{~m} / \mathrm{s}
  3. C5 m/s5 \mathrm{~m} / \mathrm{s}
  4. D10 m/s10 \mathrm{~m} / \mathrm{s}

Correct answer

A. 20 m/s20 \mathrm{~m} / \mathrm{s}

Step-by-step solution

Given, g=10 ms−2g=10 \mathrm{~ms}^{-2} and h=20 mh=20 \mathrm{~m} We have V=2gh=2×10×20=400=20 ms−1\begin{aligned}V & =\sqrt{2 g h}\\ & =\sqrt{2 \times 10 \times 20}=\sqrt{400}=20 \mathrm{~ms}^{-1} \end{aligned}
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