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NEET 2005
Exam
NEET
Year
2005
Subject
Physics
Chapter
Motion in One Dimension

NEET 2005 · Physics · Motion in One Dimension

The displacement x of a particle varies with time t as x=a e^ -a t...

The displacement xx of a particle varies with time tt as x=ae−at+Bβxx=a e^{-a t}+B^{\beta x}, where a,b,αa, b, \alpha and β\beta are positive constants. The velocity of the particle will:

Options

  1. Abe independent of β\beta
  2. Bdrop to zero when α=β\alpha=\beta
  3. Cgo on decreasing with time
  4. Dgo on increasing with time

Correct answer

D. go on increasing with time

Step-by-step solution

From question x=ae−αt+be\betatV=dxdt=−a\alphae−xt+bβeB+⇒V=−a\alphae−t+bβεβt\begin{aligned}& x=a e^{-\alpha \mathrm{t}}+b e^{\betat} \\ & V=\frac{d x}{d t}=-a \alphae^{-x t}+b \beta_e^{\mathrm{B}+} \\ & \Rightarrow \mathrm{V}=-a \alphae^{-t}+b \beta \varepsilon^{\beta t} \end{aligned}\thereforeVelocitywilldecreaseforcertainvalueofVelocity will decrease for certain value oft$.
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