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NEET2002PhysicsMotion in One DimensionActual

An object of mass 3 ~kg is at rest. Now a force F=6 t^2 i +4 j is applied on the object then the velocity of the object at t=3 ~s is:

Options

  1. A18 i +3 j
  2. B18 i +6 j
  3. C3 i +6 j
  4. D18 i +4 j

Correct answer

B. 18 i +6 j

Step-by-step solution

From question a = F m =2 t^2 i + 4 3 t j d V = (2 t^2 i + 4 3 t j ) d t Integrated both sides, We have, V =2 [ t^3 3 ] i + 4 3 [ t^2 2 ] j at t=3 sec , V = 2 3 (3)^3 i+ 4 6 (3)^2 j=18 i +6 j

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