A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 ~s is s ₁ and that covered in the first 20 ~s is s ₂ , then

Step-by-step solution

Key Idea If the particle is moving in a straight line under the action of a constant force then distance covered s = ut + 1 2 at ^2 . Since the body start from rest u =0 s = 1 2 at ^2 Now, s ₁= 1 2 a (10)^2 and s ₂= 1 2 a (20)^2 Dividing Eq. (i) and Eq. (ii), we get aligned s ₁ ~s ₂ & = (10)^2 (20)^2 s₂ & =4 ~s ₁ aligned