The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours would be :

Step-by-step solution

Given, T 1 2 = 100   hours   t = 150   hours As we know that the number of nuclide remain after n half life is given by, N = N 0 2 n ∵ 100 hours = 1 half life 150 hours   = 1 100 × 150 = 3 2 half life So, Fraction remain after 3 2 half life N N 0 = 1 2 3 / 2 = 1 2 2