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NEET 2021
Exam
NEET
Year
2021
Subject
Physics
Chapter
Nuclear Physics

NEET 2021 · Physics · Nuclear Physics

The half-life of a radioactive nuclide is 100 hours. The fraction...

The half-life of a radioactive nuclide is 100100 hours. The fraction of original activity that will remain after 150150 hours would be :

Options

  1. A12\dfrac{1}{2}
  2. B122\dfrac{1}{2\sqrt{2}}
  3. C23\dfrac{2}{3}
  4. D232\dfrac{2}{3\sqrt{2}}

Correct answer

B. 122\dfrac{1}{2\sqrt{2}}

Step-by-step solution

Given,

T12=100hoursT\dfrac{1}{2} = 100hours

t=150hourst = 150hours

As we know that the number of nuclide remain after nn half life is given by,

N=N02nN = \dfrac{{N}_{0}}{{2}^{n}}

∵100∵ 100 hours =1= 1 half life

150150 hours=1100×150= \dfrac{1}{100} \times 150

=32= \dfrac{3}{2} half life

So, Fraction remain after 32\dfrac{3}{2} half life

NN0=(12)3/2=122\dfrac{N}{{N}_{0}} = {\left(\dfrac{1}{2}\right)}^{3 / 2} = \dfrac{1}{2\sqrt{2}}

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