NEET2021PhysicsNuclear PhysicsActual
A radioactive nucleus A Z X undergoes spontaneous decay in the sequence A Z X → Z - 1 B → Z - 3 C → Z - 2 D , where Z is the atomic number of element X . The possible decay particles in the sequence are:
Options
- Aα , β - , β +
- Bα , β + , β -
- Cβ + , α , β -
- Dβ - , α , β +
Correct answer
C. β + , α , β -
Step-by-step solution
As we know due to α -decay atomic number decreases by 2 and mass no. decreases by 4   . And due to β - decay mass no. remain unchanged and atomic no. increases by 1 And due to β + decay mass no. remain unchanged but atomic no. decreases by 1 . So, option ( 3 ) is correct option.