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NEET 2013
Exam
NEET
Year
2013
Subject
Physics
Chapter
Nuclear Physics

NEET 2013 · Physics · Nuclear Physics

A certain mass of hydrogen is changed to helium by the process of...

A certain mass of hydrogen is changed to helium by the process of fusion. The mass defect in fusion reaction is 0.02866u0.02866 \mathrm{u}. The energy liberated per uu is (given 1u=931MeV1 \mathrm{u}=931 \mathrm{MeV} )

Options

  1. A2.67MeV2.67 \mathrm{MeV}
  2. B26.7MeV26.7 \mathrm{MeV}
  3. C6.675MeV6.675 \mathrm{MeV}
  4. D13.35MeV13.35 \mathrm{MeV}

Correct answer

C. 6.675MeV6.675 \mathrm{MeV}

Step-by-step solution

Here, Δm=0.02866U\Delta m=0.02866 U ∴ Energy liberated =0.02866×9314=26.74MeV=6.675MeV\begin{aligned} & \therefore \text{ Energy liberated } \\ & =\frac{0.02866 \times 931}{4}=\frac{26.7}{4} \mathrm{MeV}=6.675 \mathrm{MeV} \end{aligned}
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