The mass of a ₃ Li ^7 nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ₃ Li ^7 nucleus is nearly

Step-by-step solution

If m =1 u , c =3 10^8 ~ms ⁻¹ , then E =931 MeV ie, 1 u =931 MeV Binding energy =0.042 931=39.10 MeV Binding energy per nucleon = 39.10 7 =5.58 5.6 MeV