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NEET 2010
Exam
NEET
Year
2010
Subject
Physics
Chapter
Nuclear Physics

NEET 2010 · Physics · Nuclear Physics

The mass of a _3 Li^7 nucleus is 0.042 u less than the sum of the...

The mass of a 3Li7{ }_3 \mathrm{Li}^7 nucleus is 0.042u0.042 \mathrm{u} less than the sum of the masses of all its nucleons. The binding energy per nucleon of 3Li7{ }_3 \mathrm{Li}^7 nucleus is nearly

Options

  1. A46MeV46 \mathrm{MeV}
  2. B5.6MeV5.6 \mathrm{MeV}
  3. C3.9MeV3.9 \mathrm{MeV}
  4. D23MeV23 \mathrm{MeV}

Correct answer

B. 5.6MeV5.6 \mathrm{MeV}

Step-by-step solution

If m=1u,c=3×108 ms−1\mathrm{m}=1 \mathrm{u}, \mathrm{c}=3 \times 10^8 \mathrm{~ms}^{-1}, then E=931MeV\mathrm{E}=931 \mathrm{MeV} ie, 1u=931MeV1 \mathrm{u}=931 \mathrm{MeV} Binding energy =0.042×931=39.10MeV∴=0.042 \times 931=39.10 \mathrm{MeV}\therefore Binding energy per nucleon =39.107=\frac{39.10}{7}=5.58 ≈\approx5.6 MeV\mathrm{MeV}
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