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NEET2010PhysicsNuclear PhysicsActual

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV , respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is

Options

  1. A23.6 MeV
  2. B2.2 MeV
  3. C28.0 MeV
  4. D30.2 MeV

Correct answer

A. 23.6 MeV

Step-by-step solution

Mass of ₁ H ^2=2.01478 amu Mass of ₂ He ^4=4.00388 amu Mass of two deuterium =2 2.01478=4.02956 amu Energy equivalent to ₂ H ^2 aligned & =4.02956 1.2 & =4.4 MeV aligned Energy equivalent to ₂ He ^4=4.00388 7=28 MeV Energy released =(28-4.4)=23.6 MeV

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